Question

If the circle (x + 1)2 + (y - 3)2 = 56 is translated 1 units down and 1 units right, then the sum of the new y-intercepts is

Answer 1

@saifoo.khan can u help me

Answer 2

btw the 2 after the brackets are menats to be squared. like (x+1) to the power of 2

Answer 3

the original eq gives a center at (-1,3) . the new translated center is at (0,2)
the new eq is x^2+(y-2)^2=56
the y intercepts occur at x=0
so (y-2)^2=56
so y^2-4y+2=56
so y^2-4y-54=0

Answer 4

using the quadratic formula, we get 4+or- sqrt 232/2
or
4+15.231/2
and
4-15.231/2

Answer 5

if you add add these up, you get 4

Answer 6

thnks alot. do u mind if i ask two more questions?

Answer 7

no

Answer 8

was the answer right?

Answer 9

Determine the equation of the circle with endpoints of a diameter at (1, 4) and (-3, -6).

Answer 10

midpoint formula-ceter is at the midpoint os a diameter
(1+(-3)/2 and 4-6/2-------->center is (-1,-1) so eq is (x+1)^2+(y+1)^2=r^2

r-- use distance formula ------ sqrt of (2^2+5^2)= sqrt of 29 ----so r^2 =29

got it