A 10 kg box, sliding to the right across a rough horizontal floor, accelerates at -2 m/s^2 due to the force of friction. Calculate the coefficient of kinetic friction between the box and the floor and the magnitude of the net force acting on the box.

Question

anonymous · Answer

$$F=uN$$
u=coefficient
N=normal force

anonymous · Answer

and also F=ma

anonymous · Answer

i know the formulas i just dont know how i can get the coefficient of friction without the force of friction

stormfire1 · Answer

$$a=\frac{F}{m}=\frac{u_kmg}{m}=u_kg$$Now you have $$2.0 m/s=u_k(9.8 m/s^2)$$$$u_k=0.2041$$

stormfire1 · Answer

Note that my answer above is right although when I typed it in the 2.0 m/s should have been squared (2.0 m/s ^2=....).