Trigonometry Help!! Use identities to simplify and show work (remember you are NOT solving for x, just simplifying the expression) 1-2sin^2 x/2
\[\cos x = 1- 2\sin^2 {x \over 2}\]
Can you please show me the steps you took to find that answer. :)
shivam are you there? it says your are typing?
where?
\[\cos 2x = \cos (x+x) = \cos x \cos x - \sin x \sin x = \cos^2 x - \sin^2 x\] Now write cos^2 x = 1-sin^2 x and you will get your answer
In your case , It should be cos x = cos (x/2 + x/2)=.......
oh? what happened to your long explanation?
That was invalid :D Made some mistake. This is shoreter and easier :D
*shorter
hah..i understand this but are you saying the answer it cos^2x or cos x
@Emilyori , I gave the derivation for cos (2x). Now you try to derive it for cos (x) similarly
i am stuck so would it be \[\cos x \div2 \cos x \div2 - \sin x sinx \] or does the sin change
Shivam...I have to go,, but will return soon...please send me a message to my question if you can...thank you
Make sure you try again by seeing the above example
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