questions attachment in reply. Please help me.
which one
rationalising the denominator means multiply by a term that eliminates the radical in the denominator in this question multiply by \[\frac{\sqrt{180y}}{\sqrt{180y}}\] so the problem is now \[\frac{2\sqrt{108}}{\sqrt{180y}} \times \frac{\sqrt{180y}}{\sqrt{180y}}\] the rule for multiplying square roots is \[\sqrt{a}\times \sqrt{b}=\sqrt{ab}\] the denominator will become \[\frac{2\sqrt{108}\times \sqrt{180y}}{180y}\] you can finish the simplification.
2sqrt108\sqrt(180y) =sqrt4*sqrt108\sqrt(180y) =sqrt432\sqrt(180y) =sqrt(432\180y) =sqrt(2.4\y) =sqrt2.4\sqrt y =sqrt2.4*sqrt y\sqrt y *sqrt y =sqrt2.4y\y
sqrt is square root
here's another 2sqrt5+3sqrt7 =sqrt4sqrt5+sqrt9sqrt7 =sqrt20+sqrt63
yes it is sry
4sqrt6\sqrt30 =sqrt16sqrt6\sqrt30 =sqrt3.2 =sqrt(16\5) =4\sqrt5 =4*sqrt5\5
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