Question

Change the parametric equation into rectangular form:
y = sin(2t)
x = 2sin(squared)t

Answer 1

\[y=2\sin t\cos t\\
y^2=4\sin^2 t\ \cos^2 t\\
y^2=4\sin^2 t(1-\sin^2 t)\\
y^2=2(2\sin^2 t)-(2\sin^2 t)^2\\
y^2=2x-x^2\\
x^2-2x+y^2=0\\
(x-1)^2+y^2=1\]

Answer 2

Thank you so much! I knew it was something like that, I just couldn't quite get it to work.

Answer 3

No problem. :)