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Mathematics 18 Online
OpenStudy (anonymous):

How do you do # 6? I'll Post the question in the comments.

OpenStudy (anonymous):

OpenStudy (anonymous):

Can someone please help me. I have a quiz and a test this wek and i have to study this and i don't understand it

OpenStudy (anonymous):

week*

OpenStudy (kinggeorge):

First, you let's find the length of AC-2 so that we have that side taken care of. You have an inscribed circle in the triangle. Note that both the lines that are perpendicular to AC and BC have the same length since they're both radii of the circle. This means that if you drew a line CO, then it would be a bisector of the angle. Now, by some triangle congruencies, you have that the length of AC-2 must also be 3. Hence, the length of AC is 5.

OpenStudy (kinggeorge):

Now it's pretty straightforward. You have AC=AB=5, so it's an isosceles triangle. Also, one of the angles at the base is 60 degrees. Therefore, the other base angle is also 60 degrees. This forces the final angle to be 60 degrees, and we have an equilateral triangle. Therefore, AB=AC=BC=5, and the perimeter is \(5+5+5=15\)

OpenStudy (anonymous):

how do you conclude that all of the angles equal 60 deg

OpenStudy (amistre64):

i would go about it a little differently meself

OpenStudy (amistre64):

|dw:1336951813010:dw| the lines are the same length for each tangent of the circle

OpenStudy (anonymous):

|dw:1336951887380:dw|

OpenStudy (amistre64):

|dw:1336951874947:dw|

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