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Mathematics 19 Online
OpenStudy (anonymous):

Convergent or Divergent? .....

OpenStudy (anonymous):

\[\sum_{n=1}^{\infty} = (1/n)/(\ln(n)\sqrt{\ln^2(n)-1})\]

OpenStudy (anonymous):

If limit n tending to infinity exist then series is convergent else divergent

OpenStudy (anonymous):

The series is convergent

OpenStudy (anonymous):

Is the 2nd derivative test necessary in this problem to determine if its decreasing?

OpenStudy (anonymous):

is this a function or a sum of the series whose convergence has to be determined

OpenStudy (anonymous):

Its a series

OpenStudy (anonymous):

I determined sum to infinty is a finite number hence it is convergent Else U can assume it to be a function of integer variable and take first derivative and show it to be decreasing and also at n=1 it has finite value then it is converging

OpenStudy (anonymous):

cool, thanks a lot.

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