Question

reduce to lowest terms: (2x^3-6x^2-20x)(25-x^2)^-1

Answer 1

change to \[\Large \frac{2x^3 - 6x^2 - 20x}{25 - x^2}\] then it gets easy :D

Answer 2

\[(-4 x - 2 x^2)/(5 + x)\]

Answer 3

@EarthCitizen you can still factor out 2x

Answer 4

-2x*

Answer 5

kk, ty

Answer 6

can you show me this step by step :/

Answer 7

factor out 2x... \[\Large \frac{2x(x^2 - 3x - 10)}{25 - x^2}\] now factor out \(25 - x^2\) \[\Large \frac{2x(x^2 - 3x - 10)}{(5 - x)(5+x)}\] now factor out \(x^2 - 3x - 10\) \[\Large \frac{2x(x-5)(x+2)}{(5-x)(5+x)}\] now we factor out -1 from 5 - x \[\Large \frac{2x\cancel{(x-5)}(x+2)}{-\cancel{(x-5)}(5+x)}\]

Answer 8

thank you :)...just to clarify would simplest terms be as written above with x-5 cancelled out

Answer 9

simply \[\large \frac{-2x(x+2)}{x+5}\]

Answer 10

thanks

Answer 11

do you mind if i ask you another question?

Answer 12

((5m-10)/(8m+4))x((3m+9)/(10m-5))x((8m^2-2)/(m^2+2m-3))