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Mathematics 8 Online
OpenStudy (anonymous):

a stone is dropped into a well from the open mouth of the well the water level is at a depth of 25m the dound of splash is heard after 2.31s from its release the speed of stone in air inside the well is (g=10m/s^2)

OpenStudy (stormfire1):

What is the question asking you to solve?

OpenStudy (anonymous):

the speed of stone

OpenStudy (anonymous):

the answer is 357m/s

OpenStudy (stormfire1):

Let me find my calculator...

OpenStudy (anonymous):

we have to find the speed of stone in air inside the well

OpenStudy (stormfire1):

Well, it's impossible to drop the ball, have it fall 25m for 2.31s with g = 10 m/s^2 and have it reach 357 m/s!

OpenStudy (stormfire1):

Unless it's not being "dropped"....but thrown down instead

OpenStudy (anonymous):

we have to find the speed of stone in air inside the well plzz read this

OpenStudy (anonymous):

Did you try what @rs32623 from http://openstudy.com/study#/updates/4fb070fce4b059b524fcab29 says...

OpenStudy (stormfire1):

First, please don't post the same question twice. There's no point in doing that and it just confuses things when people aren't seeing each other's posts. Second, think about the question you're asking. If you *drop* a stone (V=0 m/s initially) and it falls with an acceleration of 10 m/s, it's not going to reach 357 m/s in only 2.31s...it will reach 23.1 m/s (acceleration * time). Are you sure the question's wording was correctly posted here?

OpenStudy (anonymous):

yes the question is correct

OpenStudy (anonymous):

157 look the question is correct

OpenStudy (anonymous):

it's a typo...they must mean the speed of SOUND in air is...

OpenStudy (anonymous):

otherwise the time the splash is heard is irrelevant

OpenStudy (anonymous):

and of course the answers are ridiculous as stormfire1 pointed out

OpenStudy (anonymous):

the time the splash is heard is 2.31s it is there in ques

OpenStudy (stormfire1):

It has to be the speed of sound in the air...that's what I was thinking.

OpenStudy (anonymous):

i think this is correct they must mean the speed of SOUND in air is

OpenStudy (anonymous):

@eseidl is right. There is a typo in the question. Secondly. It is easy @shameer1 . Why don't you show what you have tried to solve this problem ??

OpenStudy (anonymous):

yep. So we need the time it takes the stone to fall and hit the water. Then we subtract this from the total time until the sound is heard. 2.31-t. This is the time it takes the sound to travel 25m in air. From this you get the speed of sound in air.

OpenStudy (ujjwal):

and if they are trying to find speed of sound, it comes out to be 338.14 m/s ... which doesn't match with any options...

OpenStudy (anonymous):

yeah I get 338.14m/s as well

OpenStudy (anonymous):

can someone show the step plz

OpenStudy (anonymous):

Yes I also get 337.83 /s

OpenStudy (anonymous):

*m/s

OpenStudy (anonymous):

maybe we need to take air resistance into account...lol

OpenStudy (ujjwal):

haha.. but sound has nothing to do with air resistance...

OpenStudy (anonymous):

yeah but it would affect the time, t, it takes for the stone to fall and thus 2.31-t and thus our answer

OpenStudy (ujjwal):

yeah, go on find air resistance..

OpenStudy (anonymous):

ok

OpenStudy (stormfire1):

@shameer: \[h = \frac{1}{2}g t^2=25m\]\[t=2.2361s\]\[2.31s-2.2361=0.074s\]\[\frac{25m}{0.074s}=~338 m/s\]

OpenStudy (anonymous):

338.................. the ans should be 357

OpenStudy (anonymous):

@eseidl , if it is air resistance, then it becomes fluid mechanics question. In that case |dw:1336973725336:dw| rho--->density v--->volume g--->10m/s

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