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Mathematics 11 Online
OpenStudy (anonymous):

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OpenStudy (lgbasallote):

the first step itself is wrong..

OpenStudy (lgbasallote):

well the second step is also wrong even if let's say the first step was correct

OpenStudy (lgbasallote):

anyway...you should solve this by.. \[(2 \sqrt 5 + 3\sqrt 7)^2\] \[(2\sqrt 5)^2 + 2(2\sqrt 5)(3\sqrt 7) + (3\sqrt 7)^2\] \[(4)(5) + 12 \sqrt{35} + (9)(7)\]

OpenStudy (lgbasallote):

just go on with that process

OpenStudy (lgbasallote):

step 1: square of a binomial square the first term that will give you \((2\sqrt 5)^2\) twice the product of your two terms \(2(2\sqrt 5)(3 \sqrt 7)\) square the last term \((3\sqrt 7)^2\) step 2: simplify \((2 \sqrt 5)^2 = (2^2)(\sqrt 5^2) = 4 \times 5\) \[2(2 \sqrt 5)(3\sqrt 7) = (2)(2)(3)(\sqrt{(5)(7)} = 12 sqrt{35}\] \[((3\sqrt 7)^2 = (3^2)(\sqrt 7^2) = 9 \times 7\]

OpenStudy (lgbasallote):

yeah that's the final answer.....but the solution is so screwed up lol =)) there are no properties like that

OpenStudy (lgbasallote):

wolfralpha didnt show the steps to it either

OpenStudy (lgbasallote):

well continuing from my solution that's \[20 + 12 \sqrt{35} + 63\] \[83 + 12 \sqrt{35} \] that's how it's supposed to be solved

OpenStudy (lgbasallote):

you're welcome ^_^

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