Question

if csc3a=sec9a, the m 14 years ago

Answer 1

i think i stumped ya'll hahaha

Answer 2

you can rewrite this as:
\[\sin(3a) = \cos(9a)\]
then you can relate cos to sin by shifting cos to right by pi/2
\[\rightarrow \cos(9a) = \sin(9a+\pi/2)\]
thus
\[\sin(3a) = \sin(9a + \pi/2)\]
\[3a = 9a + \pi/2\]
a = -pi/12

Answer 3

lol you just pulled that outta your butt didnt you?

Answer 4

it says the answer is 7.5, its just I have no idea how to get it

Answer 5

kinda..but it works

Answer 6

lol it didnt get the answer though any ideas?

Answer 7

this has got to be the dumbest question ever

Answer 8

there are multiple answers to this question

Answer 9

you can also say
\[\cos(9a) = \sin(\pi/2 - 9a)\]
then
3a = pi/2 - 9a

a = pi/24 = 7.5 degrees

Answer 10

oh alright dang that confusing

Answer 11

\[\sin(3a)=\cos(9a)\]
\[\cos(9a)=\sin(\frac{\pi}{2}-9a)\]
So we have
\[\sin(\frac{\pi}{2}-9a)=\sin(3a)\]
But we also have
\[\sin(3a)=\sin(3a+2n \pi) \]
Though we could say the same about the other side
But anyways we have
\[\sin(\frac{\pi}{2}-9a)=\sin(3a+2 n \pi)\]
\[\frac{\pi}{2}-9a=3a+2 n \pi\]
solve for a