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moment of inertia of a solid cone about an axis passong through apex and perpendicular to the axis of symmetry
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it involves integration of small elemental disks..let me see..
k.
3/5 M R^2..if the base radius is R and mass of cone is M..
i think it's not correct!!!!!
i dunno perhaps there is some mistake in integration..its seemed wierd to me too that there isnt a height term here..
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i know the answer,but i want the proceddure exactly.It is the most expected question for me in my exam.
2/5m(r^3/4+h^2)
u in engineering ?
yup!
|dw:1336975504933:dw| volume of elementary wingspan =pi r^2 *dh now this is to be integrated..
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