Question

∫|2-x|dx intregation limits is 0 to 2?

Answer 1

\[\int_0^2|2-x|dx=\int_0^2(2-x)dx\]

Answer 2

\[\int\limits_{0}^{2} (2-x)dx\]
\[\int\limits_{0}^{2} 2x- x^2 /2\]
\[(2(2)-(2)^2 / 2 ) - ( 2(0) - (0)^2/2)\]
2

Answer 3

2 is the answer