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determine the following identity: 1 = cos2A on cos2A equals : tan2A on tanA
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Substitute \[\cos2A = {2\tan A \over 1+\tan^2 A}\] and you will get your answer
Is this your question \[{1- \cos 2A \over \cos 2A}={\tan 2A \over \tan A}\]
@Luahn ??
yes thats the question please
but its + cos2A
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1+ co2A
Ok. just write it as \[{1+ \cos 2A \over \cos 2A}\] Now substitute instead of cos 2A, \[\cos2A = {2\tan A \over 1+\tan^2 A}\] and simplify
i need to prove that 1+cos2A cos 2A equals: tan2A tanA
can i please have the method of getting to the answer
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