what is the maximum value for \[4/(4-x^2) + 9/(9-y^2)\] given that both \[x,y \in (-2,2)\] and xy=-1
Use lagrange multipliers
U know how to diffrentiate right
thats so very cool! thanx buddy..never knew about this.. and yes,,i know how to differentiaite..
differentiate*
leme try to solve here..
g(x,y) = xy+1 f(x,y) = 4/(4-x^2) + 9/(9-y^2) q(x,y,k) = f(x,y) + k(g(x,y)) = 4/(4-x^2) + 9/(9-y^2) + kxy + k dq/dx = 4(2x)/(4-x^2)^2 + ky dq/dy = 9(2y)/(9-y^2)^2 + kx dq/dk = xy + 1 on equating each to 0 , dont you think it'll be quite tedius to solve for x,y and k from here?
it gives quartic eqn in x and y.. it'll require to first convert it into cubic eqn by subsn,,then solve that eqn by converting to depressed eqn and make more substn..sir,,this is just a 4 mark objective ques..there has to be a simpler way..
Dude g(x)=xy+1 del(f)=k.del(g) g=1 will give 3 equationa and 3 unknowns
didnt get you..
\[\frac{df}{dx}i+\frac{df}{dy}j=\lambda[\frac{dg}{dx}i+\frac{dg}{dy}j]\] and \[xy=-1\]
i solve it and got the answer
whats the ans?
x=sqrt[29/21] and -sqrt[29/21]
find y accodingly
Join our real-time social learning platform and learn together with your friends!