Question

cosec x= 1/2 (x)+1
has root 0 14 years ago

Answer 1

Remember
-1 <= sin x <= 1
Therefore
-1 <= cosec x <=1

Now try :)

Answer 2

Still not sure..

Answer 3

One more question. This is your question , right
\[cosec x= {1 \over 2 }(x)+1\]

Answer 4

Yes

Answer 5

I think i solved it

Answer 6

OK. Just put instead of cosec x , 1/2(x) +1

Answer 7

Ok @NotSObright , let's see what you have done :P

Answer 8

Say y1=1/2x+1
y2=csc(x)
y1(0)=1
y1(Pi/2)=Pi/4+1

y2(0)=infinty
y2(Pi/2)=1

Since it can be proven using differentiation y1 is inceasing and y2 is decreasing on 0,pi/2
hence in order to attain boundary values graphs must cross each other

Answer 9

So what about the 0.5 and 1?

Answer 10

sorry i didn't see that
u must show at 0.5 y1<y2
and at 1 y1>y2
u might wanna use a calculator

Answer 11

But how?