Question

inverse of f(x)=x^3+1?

Answer 1

You do the exact opposite thing. In this case, the inverse of adding is subtracting and the inverse of cubing is taking the cube root. So, we can say:

\(\Large \color{midnightblue}{\rightarrow f^{-1}(x) = \sqrt[3]{x} - 1}\)

Answer 2

oops

Answer 3

Did I do it wrong?

Answer 4

thanks!

Answer 5

you need to do the opposite thing in the reverse order

Answer 6

Oops...

Answer 7

your function says
1) cube
2) add one
inverse says
1) subtract 1
2) take the cubed root
\[f^{-1}(x)=\sqrt[3]{x-1}\]

Answer 8

Okay!

Answer 9

I got it, thank you @satellite73

Answer 10

if you like, write
\[y=x^3+1\] the switch x and y get
\[x=y^3+1\] solve for y via
\[x-1=y^3\]
\[y=\sqrt[3]{x-1}\]

Answer 11

yw