Question

What is the 7th term of the geometric sequence where a1 = –3 and a5 = –768?

Answer 1

Answer is -6912.
Here how it is:
\[a7=r(a1)^{7-1}\]
\[a5=r(a1)^{5-1}\]
\[a7/a5=(a1)^{^{2}}\]
\[a7=a5\times(-3)^{2} since a1 = -3 given\]
\[a7=(-768)\times9 = -6912\]

Answer 2

thats not one of the answers in the multiple choice @vamshids

Answer 3

oh I am really sorry for this
I will tell u the right answer just now

Answer 4

its ok thanks

Answer 5

is the answer -12,288?

Answer 6

YES! thanks!

Answer 7

do you know how it came?

Answer 8

in any GP:
\[t _{n}=a(r)^{n-1}\]

Answer 9

tn is the nth term of the series.. so accordingly subsititute your a1 and a5 to get r and then find a7!! its simple

Answer 10

that helps so much! THanks!

Answer 11

welcome bye!