Question

Does anyone know the rules to adding and subtracting radicals?

Answer 1

@Hero

Answer 2

"I need a heeerrrrooooooo" :|

Answer 3

I think I have the basics. Numbers with exponents get grouped first. However, I don't know what to do with the "sqrt" numbers.

Answer 4

\[5\sqrt{6x} + 8\sqrt{14x} - 9\sqrt{6x} + 18\sqrt{14x}\]

My answer was: \[-4\sqrt{6x} + 26\sqrt{14x}\]

Answer 5

squareroot must be the same in order to add the outside number. Similar to adding like terms.

Answer 6

and you are right.

Answer 7

Kinda the same as saying

\[x+ x^2 \]

can you add these?

No because they don't have like terms.

Answer 8

So my answer was correct?

Answer 9

Yup

Answer 10

Second opinion @Hero ?

Answer 11

You can't really reduce that any further so yeah

Answer 12

Alright, thanks! :)

Answer 13

Ok, I have a question like this: \[3\sqrt{45x^3} + 2\sqrt{12} + \sqrt{27} - 3\sqrt{20x^3}\]

Answer 14

How would I solve that? >_<

Answer 15

I have no "like terms". :(

Answer 16

true but can you simplify the insides of the squareroots in order to get like terms.

For example \[\sqrt{x^2}\]

Answer 17

can you reduce that?

Answer 18

Yes. I think. :/

Answer 19

can you tell me what it reduces down to?

Answer 20

sqrt{x}

Answer 21

the

sqrt{x^2}

does not reduce to

sqrt{x}

Give it one more shot.

Answer 22

sqrt{x^2} = ????

Answer 23

I have no idea.

Answer 24

Simplifying square roots is nothing I am good at.

Answer 25

I mean... does it equal x?

Answer 26

\[\sqrt{x^2}=|x|\]

Answer 27

\[\sqrt{45x^3}= \sqrt{45}\sqrt{x^3}\]