e^x=-4 Solve the equation for x. If necessary, round your answer to two decimal places. Do not include "x =" in your answer.
e^x = -4 ln(e^x) = ln(-4) Since you cannot take the natural log of a negative number, this means that we can stop and simply say that there are no solutions.
I wrote the problem wrong it does have an In< Its In e^x=-4
ln(e^x) = -4 x*ln(e) = -4 x*1 = -4 x = -4 So the solution is x = -4
the right part not is correct because (-4) using ln can being writing -4lne that we know that lne =1 so than lne^x =xlne - and -4lne =xlne so than x=-4
e^x is always >0 so it cannot be equal to -4, No Solution.
how do you think e^(-4) = 1/(e^4) not is always greater than zero ?
@jhonyy9 you need to review exponential functions. Have you seen the graph of the function e^x. Look at the graph attached and http://archives.math.utk.edu/visual.calculus/0/exp_log.5/index.html
thank you - yes you are right good luck bye
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