Question

\frac{4x^{3}+5x^{2}+3x}{x}

Answer 1

\[\dfrac{4x^{3}+5x^{2}+3x}{x}\]

Answer 2

Divide each term by x and add.

Answer 3

HOw do you divide by x?

Answer 4

\[\frac{x^a}{x^b}=x^{a-b}\]and don't forget that\[x=x^1\]

Answer 5

Substitute it as 1?

Answer 6

yup

Answer 7

That makes it easier

Answer 8

So, the answer will only have 1 exponent and it's 1?

Answer 9

No, that's wrong..

Answer 10

as eliassab said
"divide \(each\) term by x"
you can do that using the rule I gave you

Answer 11

I don't know what to do in problems like these where there is just an x.

Answer 12

\[x=x^1\]so for example\[\frac{x^5}{x}=\frac{x^5}{x^1}=x^{5-1}=x^4\]

Answer 13

If you subtract the exponents on the top it'd be 3-2

Answer 14

but the exponent on the bottom is not a 2...

Answer 15

it's just an x.

Answer 16

read my above posts\[x=x^1\]

Answer 17

So I'd say 3-2 (-1)

Answer 18

where did -2 come from?

Answer 19

3-1 - 2

Answer 20

3-1 = 2*

Answer 21

ah... much better :)
what about the other terms

Answer 22

2-1 = 1.

Answer 23

So, can 1 be an exponent or just leave it blank?

Answer 24

and how would you divide 3x by x?

Answer 25

those are the exponents
and yes, you don't have to write the "to the 1" part

the coefficients stay, only the x's are affected here

Answer 26

for instance\[\frac{5x^4}x=5x^3\]

Answer 27

That's confusing me. It's just 3x / x.

Answer 28

2x?

Answer 29

Or does it stay the same?

Answer 30

the coefficient does not change is all I'm saying

Answer 31

The answer would be 4x^2 + 5x + 3 correct?

Answer 32

correct :)

Answer 33

Could ya help with a couple more?

Answer 34

Good Job! @careless850

Answer 35

I'm sort of in an out here, and you are supposed to post each q separately, but I'll try to help when I have the chance

Answer 36

ok

Answer 37

thanks @rebeccaskell94