The moon forms a right triangle with the Earth and the sun during one of its phases, as shown below. A scientist measures the angle x and the distance y between the Earth and the moon. Please explain clearly how the scientist can use only these two measurements to calculate the distance between the Earth and the sun.
here
you have to use a trig ratio: sin, cos, tan which one will use y and distance to sun but not the hypotenuse ?
sin = opp/hyp cos = adj/hyp tan = opp/adj -- only tan does not use hypotenuse, so to solve for distance (adjacent side) we need to use tangent --> tan(x) = y/d solve for d --> d = y/tan(x)
@dumbcow a little bit clearer please
not sure how to be any clearer...im assuming you've learned trig ratios ?
I'm super confused! I'm doing a practice sheet for my semester exam... I went over them but they didn't stick... :(
|dw:1337022770878:dw| an Acronym to use is SOH CAH TOA SOH- sin = opp/hyp CAH - cos = adj/hyp TOA - tan= opp/adj
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