Question

Two executives fly towards each other for a meeting. The first jet goes 320 mph, while the second goes 375 mph. If they started from opposite coasts 3100 miles apart, how long will it take them to meet?
Round to the nearest tenth if necessary

Answer 1

someone please help. D:

Answer 2

let they meet at a distance x from first jet.
so x=320* t
3100-x =37*t
where t is time taken for them to meet
from above two relations find x
that is your answer.

Answer 3

*375

Answer 4

I meant 3100-x = 375*t

Answer 5

it's a decimal answer :o
idk.

Answer 6

9.7 hours
8.3 hours
2.2 hours
4.5 hours

Answer 7

one of those ^ ^ ^

Answer 8

:o

Answer 9

sorry, you don't need to find x
you need to find t
and it comes out to be4.5

Answer 10

Thank's.:D

Answer 11

Let the first jet cover x miles in t hours
Then in same time the second jet will have covered 3100-x miles in same time t hours
Now time = distance/speed
time for first jet t = x/320 ---------------------- (I)
time for second jet t = (3100-x)/375 -------------- (II)
since t is same for both, we can equate the two
x 3100-x
----- = ---------
320 375
Cross-multiplying

375x = 320(3100-x)
375x = 992000 - 320x
375x + 320x = 992000
695x = 992000
x= 992000/695
x = 1427.338
substituting in (I)
t = 1427.338/320
t= 4.46

so ans is 4.5 hours