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The expression (3c)^-2 is equivalent to?
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5
?
The answer could be 1) -6c^2 2) 1/3c^2 3) 1/9c^2 4) 3/c^2
Yeah, five
There is no 5
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the rule to apply here is\[\large x^{-a}=\frac1{x^a}\]
make sure that everything in the parentheses is affected by the exponent
so would it be 1/3c^2
careful, you need to square \(everything\) in the parentheses
\[(xy)^a=x^ay^a\]
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[-6c^2]
combining both rules, we have this\[(xy)^{-a}=\frac1{(xy)^a}=\frac1{x^ay^a}\]
so there should be no 6 we "distribute" the exponent to everything in the parentheses
given that\[(xy)^a=x^ay^a\]what is\[(3x)^2\]?
\[6\times x squared\]
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3^2=9
\[1 \over 9c^2\]the answer is
that seems right
nice job :)
thanks :)
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welcome
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