Question

The expression \[ a^2 b^{-3} \over a^{-4} b^2 \] is equivalent to ?

Answer 1

have you tried to apply \[\large x^{-a}=\frac1{x^a}\]to get all positive exponents?

Answer 2

so write it as \[ a^2b^{1\3} \over a^{1\4} b^2\]

Answer 3

not quite...
the whole thing flips, not just the exponent\[\large{{a^2\cdot\frac1{b^3}}\over{\frac1{a^4}\cdot b^2}}\]

Answer 4

which can simplified...

Answer 5

\[\large{{a^2\cdot\frac1{b^3}}\over{\frac1{a^4}\cdot b^2}}=\frac{a^2\cdot a^4}{b^3\cdot b^2}\]

Answer 6

so I add the exponent?

Answer 7

yup

Answer 8

so my outcome would be \[a^6 \over b^5\]

Answer 9

yes

Answer 10

good job :)

Answer 11

thank you