Factor 4s^2+12sg+9g^2
I ended up getting (3g+2s)(3g+2s) I thought that would be considered undefined
4s^2+12sg+9g^2 4s^2+6sg+6sg+9g^2 (4s^2+6sg)+(6sg+9g^2) 2s(2s+3g)+(6sg+9g^2) 2s(2s+3g)+3g(2s+3g) (2s+3g)(2s+3g) So 4s^2+12sg+9g^2 completely factors to (2s+3g)(2s+3g)
So you have the right answer
lol but my letters are so in the wrong places
That doesn't matter, you can add in any order. This means 2s+3g is the same as 3g+2s
ok...thanks...lol
And I'm not sure of what you mean when you said "I thought that would be considered undefined"
because it seems like since they both came out with the same factors I thought it woulod cancel out
Ah i gotcha, well if you were dividing, then yes the factors would cancel (to leave you with just 1). You only have something undefined when you're dividing by zero.
But you don't have to worry about undefined terms because you're not doing any division at all.
oh ok....that was confusing me lie hell...thanks for the heads up
you're welcome
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