Question

a dolphin jumped out of the water with an initial velocity of 32 feet per second. After how many seconds did the dolphin enter the water? Use h=-16t^2+vt+s to find the answer

Answer 1

bump the problem to the top as soon as you are able to

Answer 2

ok thanks

Answer 3

4 seconds

Answer 4

thanks could u help me with another similar one please

Answer 5

can you state the equation that you used to find 4 seconds? thanks

Answer 6

use simple formula v=u+at ,where v= final velocity ,u=initial velocity ,a=acceleration due to gravity 32ft/sec and t=time
when dolphin jumps out then say at time t it reaches maximum height and its final velocity will be 0,
so 0=u-32t
u =32ft/sec so time to reach top =1second now same time to fall and reach water so total =2 seconds not 4

Answer 7

so you did not use the equation given?

Answer 8

ok thanks could you help me with a problem similar to that one please?

Answer 9

i studied in SI unites as not from UK , so cant understand the equation , basically its some form of s=ut+ 1/2 ( at^2)

Answer 10

@ewrtgsd are you not interested in the process at all? What will you do on an exam
@uzmashahid15 Thanks, I know there are other methods.

Answer 11

the equation which is given is just corollary by combining v^2=u^2 + 2as and s=ut+1/2 at ^2

Answer 12

A airplane flies 4200 km east against the wind in 6 hours. The return flight withe wind takes 5 hours. The speed of the wind remains constant. Find the speed of the plane in still air and the speed of the wind

Answer 13

i hv used directly v=u+at

Answer 14

assume airplane speed as v and wind speed as w
1st case going against wind effective speed =v-w
use distance =speed *time
speed =distance /time
so v-w=700
second case v+w =840
add both equations
v=770kmph
w=70kmph