Question

Differentiate (x^2-4x+2)(5x^3-x^2+5)

Answer 1

\[Differentiate (x ^{2}-4x+2)(5x ^{3}-x ^{2}+5)\]

Answer 2

product rule for this one
use
\[(fg)'=f'g+g'f\] with
\[f(x)=x^2-4x+2, f'(x)=2x-4,g(x)=5x^3-x^2+5,g'(x)=15x^2-2x\]

Answer 3

It says the answer should be \[25x ^{4}-84x ^{3}+42x ^{2}+6x-20\]

Answer 4

f=x2-4x+2
g=5x3-x2+5
f'=2x-4
g'=15x2-2
multiply gf'+fg' answer will be 25x4-84x3+42x2+6x-20

Answer 5

How did you get f=2x+4 and g=15x2-2 ?

Answer 6

Can you break it down so I can try to understand? I'm sorry, I'm having a hard time. :(

Answer 7

if u differentiate ax^y then you get ayx^y-1

Answer 8

so x^2 when differentiated u get 2x

Answer 9

How do you differentiate it from \[x ^{2}-4x+2\] to that 2x+4 ?
How do you diffferentiate it from \[5x ^{3}-x ^{2}+5\] to \[15x ^{2}-2\] ?