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Find the slope of the graph of the function at (-1, 3): h(x)=sqrt(x+10)
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find the derivative
I found it to be \[(\sqrt{9-h}-3)/h\] When I plug in the value of h, I still get 0/0
... you still using first principles? i take it you havent learned the derivative rules yet then
Yeah, we are just starting into this stuff
well, i spose i can run the a first principles; you most likely missed a conjugate
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\[\frac{\sqrt{x+h}-\sqrt{x}}{h}\] \[\frac{\sqrt{x+h}-\sqrt{x}}{h}*\frac{\sqrt{x+h}+\sqrt{x}}{\sqrt{x+h}+\sqrt{x}}=\frac{x+h-x}{h(\sqrt{x+h}+\sqrt{x})}\] \[\frac{h}{h(\sqrt{x+h}+\sqrt{x})}\] \[\frac{1}{\sqrt{x+h}+\sqrt{x}};when\ h=0\] \[\frac{1}{\sqrt{x}+\sqrt{x}}=\frac{1}{2\sqrt{x}}\]
just replace x with x+10 and its good
Thanks!
yep
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