How many different combinations of a 3-member debating team can be formed from a group of 16 qualified students? The answer was given to me: 560. But I'm not sure how to solve it. Thank you!

Question

kropot72 · Answer

The formula below will solve the problem.
$$nCr=\frac{n!}{r!(n-r)!}$$
n= total number of students in the team.
r = 3

Can you calculate this?

kropot72 · Answer

Sorry.
n = total number of qualified students
r = 3 (number selected for the team)

anonymous · Answer

so it would be 16!/(3!)(13!) ? Is there a way I can simplify this?

kropot72 · Answer

Yes. You can divide 16! by 13! to get 16 * 15 * 14