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Mathematics 18 Online
OpenStudy (anonymous):

24x^2y+28xy-20y

OpenStudy (anonymous):

do what?

OpenStudy (anonymous):

Factor The GCF Of The Polynomial

jimthompson5910 (jim_thompson5910):

What is the GCF of 24, 28 and 20?

OpenStudy (anonymous):

4

jimthompson5910 (jim_thompson5910):

Good, now what is the GCF of x^2y, xy and y?

OpenStudy (anonymous):

This Is The Confusing Part

jimthompson5910 (jim_thompson5910):

think of x and y as just numbers

jimthompson5910 (jim_thompson5910):

let's say that x = 2 and y = 3 if that's the case, then x^2y is 2^2*3 xy is 2*3 and y is just 3 So what do 2^2*3, 2*3 and 3 all have in common?

OpenStudy (anonymous):

So Would It Be Three Thats The Biggest Factor There

jimthompson5910 (jim_thompson5910):

yes, now generalize it...which basically means replace 3 with y (and 2 with x) So y is the common factor This is because y is present in all 3 expressions

jimthompson5910 (jim_thompson5910):

Then combine the two GCFs to get 4y This means that the GCF of 24x^2y , 28xy, and -20y is 4y

OpenStudy (anonymous):

I Got 4x(6x+7x+5)........?????

jimthompson5910 (jim_thompson5910):

It should be 4y(6x^2 + 7x - 5) From there, can you factor 6x^2 + 7x - 5 further?

OpenStudy (anonymous):

I Don't Think So

jimthompson5910 (jim_thompson5910):

It turns out that you can. Here's why Multiply the first coefficient and the last term: 6*(-5) = -30 Now find two numbers that multiply to -30 and add to 7. These two numbers are 10 and -3 Because such two numbers exist, this means that we can factor it further

jimthompson5910 (jim_thompson5910):

So break up 7x into 10x-3x and factor by grouping 6x^2 + 7x - 5 6x^2 + 10x-3x - 5 (6x^2+10x)+(-3x-5) 2x(3x+5)-1(3x-5) (2x-1)(3x-5) So 6x^2 + 7x - 5 factors to (2x-1)(3x-5) Therefore, 24x^2y+28xy-20y completely factors to 4y(2x-1)(3x-5)

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