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solve for x if m<0:y>mx+b
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y > mx+b y-b > mx (y-b)/m < x x > (y-b)/m Note: since m < 0, this means that the sign will flip when you divide both sides by m.
would the y-b be divided by m?
You mean is there a way to take (y-b)/m and simplify it further?
what I wrote above as the answer is \[\Large x > \frac{y-b}{m}\]
when y-b>mx would you divide by mx?
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yes, this allows you to isolate x
since m is negative, this will flip the inequality sign
so it would be \[y-b \div mx \]
yes, but you're not dividing by x since you want to solve for it
okay thank you i understand it now!
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that's great, you're welcome
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