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Mathematics 53 Online
OpenStudy (anonymous):

Help, picture attached. Show working thanks I only need help with 1.d) which is finding the domain of A(x)

OpenStudy (anonymous):

OpenStudy (anonymous):

what's your area function?

OpenStudy (anonymous):

your area should be a quadratic (upside down parabola) since area is positive, set your area function = 0. you'll get the two x-values that make your area zero. the x's between these two values is your domain of A(x).

OpenStudy (anonymous):

yep but how do u solve it? 0=10y + xy -x^2

OpenStudy (anonymous):

What do you mean, how do you solve it? You said you need the domain?

OpenStudy (anonymous):

yeh how do u solve 0=10y + xy - x^2?? @dpaInc said i need to solve it first to figure out that domain.

OpenStudy (anonymous):

If you're asking how to solve for y, you add x^2 to both sides so you get x^2=10y+xy Pull a y out front of the right side and you get x^2=y(10+x) And therefore y=x^2/(10+x)

OpenStudy (anonymous):

your area is in terms of two variables. get it in terms of 1 by using the perimeter constraint.

OpenStudy (anonymous):

Is this for a Calculus class?

OpenStudy (anonymous):

so i can use the equation from part c?

OpenStudy (anonymous):

nope, i haven't learnt Calculus yet.

sam (.sam.):

domain of y=x^2/(10+x) \[{x \in \mathbb{R}~:x+10 \neq 0}\]

OpenStudy (anonymous):

yes @JayDS

OpenStudy (anonymous):

um i solved it but i get the wrong x values?

OpenStudy (anonymous):

\[0=2x ^{2}+16x+260\] \[-260 = -2x ^{2} + 16x\] \[-260 -2x(x-8)\] \[-2x = -26\] or x-8=-260 x = 130 or x = -252

OpenStudy (anonymous):

-2x = -260*

OpenStudy (anonymous):

your area function should be A(x) = -2x^2 + 16x + 260

OpenStudy (anonymous):

yep can u solve it? when i solved it i seemed to have got the wrong answers as shown in my working above.

OpenStudy (anonymous):

setting A(x)=0, i get irrational roots...

OpenStudy (anonymous):

hmm i'm not too sure but the answers say the domain is (0, 13) and i'm not sure how they got that

OpenStudy (anonymous):

hang on.. my perimeter equation was wrong...

OpenStudy (anonymous):

the P equation is y = -x + 26

OpenStudy (anonymous):

perimeter*

OpenStudy (anonymous):

hmmm i keep getting the same thing... my perimeter is the same

OpenStudy (anonymous):

wait.. look at you perimeter equation... x can only be as big as y.

OpenStudy (anonymous):

it doesn't make sense if x is bigger than y (according to the figure).

OpenStudy (anonymous):

so the most x can get is 13... the least is 0.

OpenStudy (anonymous):

um i don't quite get it

OpenStudy (anonymous):

the Perimeter equation is y= - x + 26 but how can you tell that x at most is 13? u can't.

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