\[\log_{5} \log_{3} \log_{2^x} =0 then x is?

Question

\[\log_{5}  \log_{3}   \log_{2^x} =0   then x is?

anonymous · Answer

\[\log_{5}  \log_{3}   \log_{2^x} =0   then x is?

anonymous · Answer

it is log x to the base 2.......

anonymous · Answer

log5 log3 log x to the base 2 =0 then x is ?

anonymous · Answer

plzz answer this with steps......

mertsj · Answer

Is it really the product of those logs?

mertsj · Answer

$$\log_{2}5(\log_{2}3)(\log_{2}x)=0   $$

mertsj · Answer

Is that the problem?

anonymous · Answer

log5 log3 log x to the base 2 =0 then x is ?

anonymous · Answer

log5  log3  log2^x

anonymous · Answer

this is the problem

anonymous · Answer

log2^x ( base 2)

mertsj · Answer

I am here.  And I am not sure what the problem is.  I still don't know if it is the product of the three logs or what.  What class are you taking?  Are you sure there are not plus or minus signs between those logs?  Is there more to the problem such as the logs of 5 and 3 are given?

anonymous · Answer

it is the product  i will take a photo

mertsj · Answer

ok

mertsj · Answer

Please include the directions with the picture.

anonymous · Answer

log5 log 3 log2^x =0 find x?

anonymous · Answer

$$\log_{5}   \log_{3}   \log_{2^{x}} =0 find $$ x

anonymous · Answer

is it clear

mertsj · Answer

So it's not a product.

mertsj · Answer

It's the log of the log of the log.  And remember that logs are exponents.  And since you have a list of answers there, I would plug them in and see which one works.

kropot72 · Answer

Is 1 included in the answers?

anonymous · Answer

log5 log 3 log2^x =0 find x?  the  question is to find x  how it came log of log of log.....................the ans=8 plzz solve for it

mertsj · Answer

For example if x is 8 then you have 
$$\log_{2}8=3 $$

anonymous · Answer

yes  u r right

mertsj · Answer

And the problem becomes:
$$\log_{5}\log_{3}3  $$

anonymous · Answer

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