50 g of zinc blende (znS) containing only silica as impurity is roasted to convert all the znS in itto znO the result in decrease in mass of 6g due to roasting the weight of the impurity in the sample is (zn=65.4)

Question

anonymous · Answer

@shivam_bhalla plzz help!

anonymous · Answer

What are we supposed to find?

anonymous · Answer

@zaphod we have to find the weight of the impurity in the sample

anonymous · Answer

plzz  can any one solve it.... @shivam_bhalla  plzz come

aravindg · Answer

tell me what u hav attempted in this qn

anonymous · Answer

i didnt understand how to do

anonymous · Answer

i mean what to do first plzz tell the steps and i will do it

anonymous · Answer

I am back

anonymous · Answer

plzz  help

anonymous · Answer

i think no one knows this plzz help

anonymous · Answer

2ZnS + 2O2 --->2 ZnO + SO_2

anonymous · Answer

@shameer1 ,. Now apply similar approach as you did for the previous problem

anonymous · Answer

6g is lost

anonymous · Answer

plzzz i think it is difficult can u plzz write the complete answer for this question only plzzz

anonymous · Answer

@shammer1, calculate number of moles of ZnS.  Then calculate the number of moles of ZnO.  The difference in number of moles will give you noumber of moles of the impurity.  You know the molecular mass of Si.  So, you can find the weight of SI present as impurity

aravindg · Answer

@shameer1  did u try that ?

anonymous · Answer

yes but not getting shivam told to miize the mole if i subtract the ans=0

anonymous · Answer

@AravindG , I will make sure that I will never give a solution to @shameer1 in future unless he shows his attempt to solve the problem

aravindg · Answer

thanks.

aravindg · Answer

@shivam_bhalla  he has posted a new qn look and see the comment in it