Question

Could someone help me on this question please:

If g(x) = 3+x+e^x, find g^-1(4)

Answer: g^-1(4) = 0

Answer 1

I replaced all x's with y's and came up with this, x-3=y+e^y and I'm not sure how to solve for y from here

Answer 2

*all x's with y's and all y's with x's

Answer 3

You need to find \[g ^{-1} (4)\]
This means you need to find x for which g(x)=4
You agree with this?

Answer 4

Yeah, that makes sense so far

Answer 5

Though how would I do that? Is that just plug and check?

Answer 6

so
\[4=3+x+e^x\]
Yeah here if we plug x=0
We'll get 4
so x=0 is the answer

Answer 7

I think we can only plug and check:(

Answer 8

Oh okay, thanks for your help, I appreciate it.