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Find the slope of the tangent line f(x)=x^2 when x=1
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got your derivative?
calculus?
derivative at x=1 is the slope of the tangent at x=1
then using point-slope form \[y-y1=m(x-x1)\] you'll get the tangent line at that point
in order to find y, you just plug f(1)
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make sense?
Thanks:)
did you get the answer?
\[y'=2x\] \[f'(1)=2(1)=2=m\] \[f(1)=(1)^2=1=y1\] \[y-1=2(x-1)\] \[y=2x-1\]
The slope is 2 :)
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