Question

find the slope of the line passing through (1,5) and 4,-2)

Answer 1

m = (y2-y1)/(x2-x1)



m = (-2-5)/(4-1)



m = (-7)/3



m = -7/3



So the slope of the line that passes through the two points is -7/3

Answer 2

can you tel me how to get there and etc

Answer 3

nvm i got it u just subtract

Answer 4

The first point is (x1,y1), which is really (1,5)


So (x1,y1) = (1,5)


This means x1 = 1 and y1 = 5

Answer 5

The same thing applies to the second point

Answer 6

thank you.. so you just subtract basically

Answer 7

yes, subtract the corresponding coordinates (in the same order) and reduce

Answer 8

can you help me do this.. change 2x+3y = 6 into slope intercept form

Answer 9

2x+3y = 6


3y = 6 - 2x


y = (6-2x)/3


y = 6/3 - 2x/3


y = 2 - 2/3x


y = -2/3x + 2

Answer 10

can you work me through it on how to do it step by step

Answer 11

write the equation of the line with y-intercept of 3 and slope 6

Answer 12

The general equation is y = mx+b where m is the slope and b is the y-intercept


We're given a slope of 3. So m = 3. We're also given a y-intercept of 6. So b = 6


This means that the answer is y = 3x+6