A wooden pyramid, 3 inches tall, has a square base. A carpenter increases the dimensions of the wooden pyramid by a factor of 6 and makes a larger pyramid with the new dimensions. Describe in complete sentences the ratio of the volumes of the two pyramids.
Do you know the formula for calculating the volume of a square-based pyramid?
is it V=1/3*b^2*h
Right. If the carpenter increase the dimensions of the pyramid by a factor of 6, how would you rewrite the equation for the volume?
Close.\[V=\frac13(6b)^2*6h\]The ratio of the volumes of the two pyramids would be given by \[\left( V _{6}\over V _{1} \right)=\left( \frac13(6b)^2*6h \over \frac 13 b^2+h\right) \]
Can you simplify the ratio?
Sorry, I got that last equation wrong. It should have been\[\left( V _{6}\over V _{1} \right)=\left( \frac13(6b)^2*6h \over \frac 13 b^2*h\right)\]
o wow okay!...so whats the b? i think the h is 3?
You should simplify the expression. Do you know how?
I think i do but i cant remember right now!
Put like terms together. The terms that are exactly the same on the top and bottom would cancel. \[\left( V _{6}\over V _{1} \right)=\left( \frac13(6b)^2*6h \over \frac 13 b^2*h\right)=\left( \frac13 \over \frac 13\right)\left( 6b \over b \right)^2\left( 6h \over h \right)\]What would be left?
(1)(5b)^2(5h)??
Let's take one term\[\left( 6b \over b \right)^2=6^2\left( b \over b \right)^2=?\]
Okay. \[6^2\left( b \over b \right)^2=6^2(1)^2=6^2(1)=6^2\]
omg o okay i got you!
v=6^2*6?
Correct!! So the ratio would be\[\left( V _{6}\over V _{1} \right)=\left( \frac13 \over \frac 13\right)\left( 6b \over b \right)^2\left( 6h \over h \right)=(1)(6^2)(6)=6^3\]
So what sentence can you say about the ratios of the volumes of the two pyramids?
The volume larger pyramid (where the dimensions were 6 times as great) is ______times the volume of the smaller pyramid.
6 times?
Nope, 6 times 6 times 6.....or 6^3 or 216 times greater
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