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How do i do this? log(3)2c= -2
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3^-2=2c
solve for c
how you get 3^-2=2c
well log is just the inverse function of an exponent logb x = y is b^y=x And plug in your numbers and variables
\[b=a^{x}\] then \[x=\log_{a}b \] so the power becomes the subject of the equation but we are going back hence \[3^{-2}=2c\]
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so how do i solve for c
\[c=1/18\]
how do i solve for c
divide by 2 both sides and evaluate
\[2c=1/3^{2}\] \[2c=1/9\] \[c=1/9\div2=1/18\]
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