Question

A rocket is launched into the air and can be modeled by the equation h=32t-4t^2 where h represents height of rocket and t is seconds.
find vertex?
how long it'll take to reach max heigth

Answer 1

for vertex, -b/2a

Answer 2

max heighth?

Answer 3

Or convert the equation to completing square form,

-4(t-4)^2 +64

So, at time 4s it will at max height of 64m

Answer 4

how would i find the x and y intercepts of that equation

Answer 5

set the thing in bracket equal to zero.

t - 4= 0
t = 4

Answer 6

When you have find the y-intercept, make x = 0

and when x-intercept, make y = 0

Answer 7

and thats how i'd find them? just one intercept for both?

Answer 8

2 for x.
1 for y.

Answer 9

so what would be the answer for this equation?

Answer 10

which one?

Answer 11

the word problem at the beginning

Answer 12

in finding the x and y intercepts

Answer 13

the question never asked for an equation

Answer 14

When you have find the y-intercept, make x = 0

and when x-intercept, make y = 0

Answer 15

h=32t-4t^2

Answer 16

I NEED HELP

Answer 17

back.

Answer 18

y-int explains the height when time was zero.
x-ints explain the time for the rocket being in air

Answer 19

Well my teacher marked that wrong

Answer 20

That's impossible.
teacher must be sleepy.

Answer 21

I'll aske her. But how would you find the intercepts from an equation like h=32t-4t^2
i dont get it

Answer 22

When you have find the y-intercept, make t = 0

and when x-intercept, make y = 0

Answer 23

When you have find the y-intercept, make t = 0
h = 32t - 4t^2
h = 32(0) - 4(0)^2
h = 0

and when x-intercept, make y = 0
h=32t-4t^2
0=32t-4t^2

Solve.

Answer 24

would i divide by 4 to get h=8t-t^2?

Answer 25

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Answer 26

then i'd take 8t to the other side and get t^2=8?

Answer 27

t^2 -8t = 0
t(t-8) = 0

t = 0 and t = 8

two values

Answer 28

ohh..so you factored the t^2 and then did the opposite value.......

Answer 29

Yes Lexi.

Answer 30

okay..thank you very much..buh bye

Answer 31

Welcome