Question

Write the standard equation for the circle center (–6, 7), r = 9.

Answer 1

(x-h)^2+(y-k)^2 = r^2


(x-(-6))^2+(y-7)^2 = 9^2


(x+6)^2+(y-7)^2 = 81

Answer 2

can you help me with 2 more?

Answer 3

sure I can help you out

Answer 4

Write the standard equation for the circle center (–6, –8), that passes through (0, 0).

Answer 5

distance from (-6,-8) to (0,0) is the radius


d = sqrt((0-(-6))^2+(0-(-8))^2)



d = sqrt((0+6)^2+(0+8)^2)



d = sqrt((6)^2+(8)^2)



d = sqrt(36+64)



d = sqrt(100)



d = 10



So exact distance between the two points is 10 units.


This means that the radius is 10. So r = 10


The center is (-6,-8), so h = -6 and k = -8


(x-h)^2+(y-k)^2 = r^2


(x-(-6))^2+(y-(-8))^2 = 10^2


(x+6)^2+(y+8)^2 = 100


So the equation of the circle is (x+6)^2+(y+8)^2 = 100

Answer 6

The center of a circle is (h, 7) and the radius is 10. The circle passes through (3, –1). Find all possible values of h.
i think the answer is 9,-3

Answer 7

You are 100% correct. Nice job.

Answer 8

ahhhhhh thank you sooooooooo much!!!!!!

Answer 9

you're welcome