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Mathematics 17 Online
OpenStudy (anonymous):

how do you find the range and domain of (x+2)^2

OpenStudy (anonymous):

\[(x+2)^{2}\]

OpenStudy (anonymous):

You find the domain by checking the possible values x can have. in this case, it's R. You find the range by checking the values y or f(x) can have. in this case, y>=0

OpenStudy (anonymous):

you first have to expand it and then grph it. thats the easiest way i kno.....

OpenStudy (anonymous):

I need to know how to solve it using algebra

OpenStudy (anonymous):

does anyone know how?

OpenStudy (anonymous):

i just told you

OpenStudy (anonymous):

what equation could i set up?

OpenStudy (anonymous):

it doesn't need any equation in this question. x can have any value because it's not in denominator or under radical. so domain is R y will be possitive because it's the result of a squared equation which is always positive. so range is >= 0

OpenStudy (anonymous):

ohhh. okay. What if it was 1/(x+2)^2

OpenStudy (anonymous):

in that case, u should find the value of x where x+2 = 0. and the domain will be everything EXCLUDING that value.

OpenStudy (anonymous):

thanks!

OpenStudy (anonymous):

no problem

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