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OpenStudy (anonymous):
\[(x+2)^{2}\]
OpenStudy (anonymous):
You find the domain by checking the possible values x can have. in this case, it's R.
You find the range by checking the values y or f(x) can have. in this case, y>=0
OpenStudy (anonymous):
you first have to expand it and then grph it. thats the easiest way i kno.....
OpenStudy (anonymous):
I need to know how to solve it using algebra
OpenStudy (anonymous):
does anyone know how?
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OpenStudy (anonymous):
i just told you
OpenStudy (anonymous):
what equation could i set up?
OpenStudy (anonymous):
it doesn't need any equation in this question.
x can have any value because it's not in denominator or under radical. so domain is R
y will be possitive because it's the result of a squared equation which is always positive. so range is >= 0
OpenStudy (anonymous):
ohhh. okay. What if it was 1/(x+2)^2
OpenStudy (anonymous):
in that case, u should find the value of x where x+2 = 0. and the domain will be everything EXCLUDING that value.
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