solve : ra-2/a-4
This is a bit incomplete I'm afraid. There is no equation to solve.
This is called an expression. What would you like to do with the expression?
Are there some numbers for a and r to which you would like to evaluate the expression?
rationalize the denominator
no the r=radical
\[\sqrt{\frac{a-2}{a-4}}\] ?
yesss sry first time :$
wait no the second
\[\frac{a-2}{\sqrt{a-4}} ?\]
denominator has no radical and the 2 on the numerator is seperate
wait ill draw
Ok that might be better Sorry.
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rationalize the denominator, i think i miss a step, i dont know how to factor out the a from the neumerator, anyway please help with the steps
Well the thing is there is nothing to rationalize in the denominator Do you mean rationalize the numerator because that is where the radical is at
wow lool sry so many questions ive done this is my first num, yes sry num not deno :$
Its cool! :) \[\frac{\sqrt{a}-2}{a-4} \cdot \frac{\sqrt{a}+2}{\sqrt{a}+2} \text{ always multiply top and bottom by the conjugate }\] The conjugate is just the operation switches
yupp
Like what I mean is the conjugate of a+b is a-b The conjugate of a-b is a+b The conjugate of -a+b is -a-b The conjugate of -a-b is -a+b
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