how do you find the distance between 7x-5y+4=0 and y=7/5x-10?
i would like to say the distance between their y intercepts.....
|dw:1337130772649:dw| see?
so just find the difference then take the absolute value
if you wanna know how i found the y-intercepts...it's the constants
The difference -10 and 4 is 14 units. so you wouldn't use the distance formula?
well you can....but that is kinda pointless...the coordinates are (0,4) and (0,-10) try the distance formula
\[\Large \sqrt{(0 - 0)^2 + (-10 - 4)^2} = \sqrt{14^2} = 14\]
Ahh i'm so slow...ok that make sense. The only thing is that the answers provided are a. 6.3 b. 6.28 c. 6.29 d. 6.31
hu-what o.O @zepp please help im confused @_@
The question says find the distance between the lines with these equations
but that's what we did.....?
so distance between y-intercepts doesnt work =_=
Distance between x-intercepts then? o.o
|dw:1337131447918:dw| maybe it should be measured that way..
Ohhhh
Are those two functions perpendicular? if they are, we can use a perpendicular function that passes through two points.
functions parallel*
Yup, they are parallel.
@lgbasallote The line you drew between the two functions aren't necessarily perpendicular to these functions
that's why i called you :P
lol, doing it, had some issue with my calculator's program, hold on >.>
Then I need to find the distance, and that distance must be equal for each perpendicular corresponding points (idk how to formulate it but. oh well) So I'm going to find a function that's perpendicular to those two functions.
Now, let's take our slope, 7/5 and twist it, -5/7
now you have the slope of the perpendicular function, find the two points and calculate the distance. |dw:1337132792352:dw|
Join our real-time social learning platform and learn together with your friends!