Question

log5(4)+log5(2x)=log(5)24

Answer 1

\[\log_{5} 4+\log_{5} 2x=\log_{5} 24\]

Answer 2

Is the question like this?
\[log_5(4)+log_5(2x)=log_524\]

Answer 3

If it is, then
\[log_5(4)+log_5(2x)=log_524\]\[log_5(4 \times2x)=log_524\]\[4(2x)=24\]
I think you can solve it :)

Answer 4

@Callisto does x=10

Answer 5

no....
4(2x) = 24
8x = 24
x = ... ?

Answer 6

oh. x=3

Answer 7

Yes :)

Answer 8

what if the = does not have log

Answer 9

like this log10(4)+log10 (w)=2

Answer 10

hmm... \[2=log_{10}10 = log_{10}10^2\]

Answer 11

no, the example i showed you

Answer 12

So,
\[log_{10}(4)+log_{10} (w)=2\]\[log_{10}(4)+log_{10} (w)=log_{10}10^2\]\[log_{10}(4w)=log_{10}10^2\]\[4w = 10^2\]Solve w

Answer 13

oh so if the 2 is a 4 it would be 10^4

Answer 14

If the base is still 10, then yes :)

Answer 15

k, thx so, if the bas ewas 6 it would be 6^2

Answer 16

Yes!~

Answer 17

k, thx bro.

Answer 18

Welcome :) it's a sis though lol

Answer 19

oh sorry sis! :)