A card is drawn from a standard deck of cards. The card is not replaced, and a second one is drawn. Find the probaility. P(queen of hearts or a red card) P(queen of hearts or 10)
Hypergeometric distribution applies
i could be wrong on this
oh i didnt read first part right
26of 52 then 5 of 51 if didnt draw q hearts or red ten first time
i dont get it
Do you want to go thru the second part of the question?
if u can :)
There are 26 red cards including the queen of hearts and a total of 52 cards in a standard pack. The probability of getting a queen of hearts or a red card in a sample of two without replacement is given by: \[\frac{\left(\begin{matrix}26 \\ 1\end{matrix}\right)\left(\begin{matrix}26 \\ 1\end{matrix}\right)}{\left(\begin{matrix}52 \\ 2\end{matrix}\right)}\] \[=\frac{26}{51}\]
There are 4 cards with value 10 and one queen of hearts card giving a total of 5. The probability of getting a queen of hearts or a 10 card in a sample of two without replacement is given by: \[\frac{\left(\begin{matrix}5 \\ 1\end{matrix}\right)\left(\begin{matrix}47 \\ 1\end{matrix}\right)}{\left(\begin{matrix}52 \\2\end{matrix}\right)}\] \[=\frac{235}{1326}\]
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