Question

solve log2(4) - log2(x+3)=log2(8)

Answer 1

are those "2"s the base of logarithms?

Answer 2

Yessir

Answer 3

yes

Answer 4

Then
4/(x+3) = 8
4 = 8(x+3)
x+3 = 1/2
x = 1/2 - 3
x= -5/2

Answer 5

wait why would you put the (x+3) next to the 8

Answer 6

you multiply both sides by (x+3) to remove it from denominator.

Answer 7

k, but how did you get t(x+3) by it self

Answer 8

\[\log_{2}4/(x+3)=\log_{2} 8\]
\[4/(x+3)=8\]

Answer 9

You can remove the logarithms from both sides of the equation in such a fashion if they have the same base.

Answer 10

\[\log_2(4)-\log^2(x+3)=\log^2(8)\\\\ \log_2(2^2)-\log_2(x+3)=\log_2(8)\\\\ (2)-\log_2(x+3)-\log_2(8)=0\\2-\log_2(x+3)-(3)=0\\-1-\log_2(x+3)=0\\log_2(x+3)=1*-1\\x=\frac{-5}{2} \]