Question

Given the formula y=ax^(n-3), find n when y=192, a= 6, and x=2.

Answer 1

plug the numbers into the equation and solve for n
you will need to use logarithms to solve for n

using the rule

log(x^(y)) = (y)log(x)

Answer 2

i understand that it will be 192=(6)(2)^(n-3) but im not sure how solve it.

Answer 3

plug the numbers in and take the log of both sides

Answer 4

I dont understand what log is.

Answer 5

\[
192 = 6 2^{n-3}\\
32 = 2^{n-3}
\]
What power of 2 gives you 32?
Read on
\]
2^2= 4
2^3= 8
2^4=16

\]
So
\[
2^{x} = 32
\]
How much is x?

Answer 6

To finish it
n-3 = x
n = 3+x