Mathematics
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OpenStudy (anonymous):
solve 4^(3x)=12
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sam (.sam.):
\[3x=\log_4{12}\]
sam (.sam.):
x=0.597493475
OpenStudy (anonymous):
how you find x though
sam (.sam.):
do you have a scientific calculator?
OpenStudy (anonymous):
ya
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sam (.sam.):
it it with base 10 only?
sam (.sam.):
3x=\log_4{12}
\[3x=\frac{\log_{10}12}{\log_{10}4}\]
\[x=\frac{\log_{10}12}{3\log_{10}4}\]
OpenStudy (anonymous):
I don't know
OpenStudy (anonymous):
so its log 12/log10
sam (.sam.):
its log base10 12 over 3 log base10 4
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sam (.sam.):
we can do this in a different way if this is confusing
OpenStudy (anonymous):
k, in different waythen
sam (.sam.):
you learn natural logarithm?
OpenStudy (anonymous):
ya, I think.
sam (.sam.):
its ln()
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OpenStudy (anonymous):
yes
sam (.sam.):
so , 4^(3x)=12
take the ln() of both sides,
ln(4^(3x)=ln(12)
OpenStudy (anonymous):
That's it?
sam (.sam.):
from a rule,\[ \ln(x^ y) = y \ln(x)\]
So,
\[\ln(4^{3x})=\ln(12)\]
turns into
\[3x\ln(4)=\ln(12)\]
OpenStudy (anonymous):
k, then what. I find the ln of 4 and 12 and subtract them
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sam (.sam.):
divide both sides by ln(4)
OpenStudy (anonymous):
then I divide that answer by 3?
sam (.sam.):
yes
OpenStudy (anonymous):
is the answer 0.59749375
sam (.sam.):
yes
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OpenStudy (anonymous):
thanks
sam (.sam.):
np