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Mathematics 19 Online
OpenStudy (anonymous):

solve 4^(3x)=12

sam (.sam.):

\[3x=\log_4{12}\]

sam (.sam.):

x=0.597493475

OpenStudy (anonymous):

how you find x though

sam (.sam.):

do you have a scientific calculator?

OpenStudy (anonymous):

ya

sam (.sam.):

it it with base 10 only?

sam (.sam.):

3x=\log_4{12} \[3x=\frac{\log_{10}12}{\log_{10}4}\] \[x=\frac{\log_{10}12}{3\log_{10}4}\]

OpenStudy (anonymous):

I don't know

OpenStudy (anonymous):

so its log 12/log10

sam (.sam.):

its log base10 12 over 3 log base10 4

sam (.sam.):

we can do this in a different way if this is confusing

OpenStudy (anonymous):

k, in different waythen

sam (.sam.):

you learn natural logarithm?

OpenStudy (anonymous):

ya, I think.

sam (.sam.):

its ln()

OpenStudy (anonymous):

yes

sam (.sam.):

so , 4^(3x)=12 take the ln() of both sides, ln(4^(3x)=ln(12)

OpenStudy (anonymous):

That's it?

sam (.sam.):

from a rule,\[ \ln(x^ y) = y \ln(x)\] So, \[\ln(4^{3x})=\ln(12)\] turns into \[3x\ln(4)=\ln(12)\]

OpenStudy (anonymous):

k, then what. I find the ln of 4 and 12 and subtract them

sam (.sam.):

divide both sides by ln(4)

OpenStudy (anonymous):

then I divide that answer by 3?

sam (.sam.):

yes

OpenStudy (anonymous):

is the answer 0.59749375

sam (.sam.):

yes

OpenStudy (anonymous):

thanks

sam (.sam.):

np

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